6k^2+6k-18=-6

Solution for 6k^2+6k-18=-6 equation:

6k^2+6k-18=-6

We move all terms to the left:

6k^2+6k-18-(-6)=0

We add all the numbers together, and all the variables

6k^2+6k-12=0

a = 6; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·6·(-12)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*6}=\frac{-24}{12}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*6}=\frac{12}{12}
=1
$